leetcode 398. Random Pick Index

Given an array of integers with possible duplicates, randomly output the index of a given target number. You can assume that the given target number must exist in the array.

Note:
The array size can be very large. Solution that uses too much extra space will not pass the judge.

Example:


int[] nums = new int[] {1,2,3,3,3};
Solution solution = new Solution(nums);
// pick(3) should return either index 2, 3, or 4 randomly. Each index should have equal probability of returning.
solution.pick(3);
// pick(1) should return 0. Since in the array only nums[0] is equal to 1.
solution.pick(1);

  • my solution is memory limit exceeded

    1
    2
    3
    4
    5
    6
    7
    8
    9
    10
    11
    12
    import random
    import collections
    class Solution(object):

    def __init__(self, nums):
    self.nums = nums

    def pick(self, target):
    index_dict = collections.defaultdict(list)
    for i,n in enumerate(self.nums):
    index_dict[n].append(i)
    return random.choice(index_dict[target])
  • Reservoir Sampling solution

    1
    2
    3
    4
    5
    6
    7
    8
    9
    10
    11
    12
    13
    14
    15
    16
    17
    import random
    import collections
    class Solution(object):

    def __init__(self, nums):
    self.nums = nums

    def pick(self, target):
    count, index = 0, 0
    for i, n in enumerate(self.nums):
    if n == target:
    count += 1
    rand = random.randint(1, count)
    if rand == count:
    index = i

    return index